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7n^2+45n+50=0
a = 7; b = 45; c = +50;
Δ = b2-4ac
Δ = 452-4·7·50
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-25}{2*7}=\frac{-70}{14} =-5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+25}{2*7}=\frac{-20}{14} =-1+3/7 $
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